Answer
The first five terms are:
$a_1 = 3;
\\a_2= \dfrac{9}{2};
\\a_3= 9;
\\a_4= \dfrac{81}{4};
\\a_5= \dfrac{243}{5}$
Work Step by Step
Substitute $n=1, 2, 3, 4, 5$ to obtain:
$a_1 = \dfrac{3^1}{1}=\dfrac{3}{1}=3;
\\a_2= \dfrac{3^2}{2}=\dfrac{9}{2};
\\a_3= \dfrac{3^3}{3}=\dfrac{27}{3}=9;
\\a_4= \dfrac{3^4}{4}=\dfrac{81}{4};
\\a_5= \dfrac{3^5}{5}=\dfrac{243}{5}$
