Answer
Option (d)
Work Step by Step
RECALL:
The standard form of the equation of a circle is:
$(x-h)^2+(y-k)^2=r^2$
where $r$ = radius and $(h, k)$ is the center
Thus, the standard equation of a circle whose center is at $(3, -5)$ and has a radius of $6$ is:
$(x-h)^2+(y-k)^2+r^2
\\(x-3)^2+[y-(-5)]^2 = 6^2
\\(x-3)^2+(y+5)^2=36$
Therefore, the answer is Option (d).
