## College Algebra (10th Edition)

RECALL: The standard form of the equation of a circle is: $(x-h)^2+(y-k)^2=r^2$ where $r$ = radius and $(h, k)$ is the center Thus, the standard equation of a circle whose center is at $(3, -5)$ and has a radius of $6$ is: $(x-h)^2+(y-k)^2+r^2 \\(x-3)^2+[y-(-5)]^2 = 6^2 \\(x-3)^2+(y+5)^2=36$ Therefore, the answer is Option (d).