College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.4 - Circles - 2.4 Assess Your Understanding - Page 186: 7


Option (d)

Work Step by Step

RECALL: The standard form of the equation of a circle is: $(x-h)^2+(y-k)^2=r^2$ where $r$ = radius and $(h, k)$ is the center Thus, the standard equation of a circle whose center is at $(3, -5)$ and has a radius of $6$ is: $(x-h)^2+(y-k)^2+r^2 \\(x-3)^2+[y-(-5)]^2 = 6^2 \\(x-3)^2+(y+5)^2=36$ Therefore, the answer is Option (d).
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