Answer
Standard Form: $\color{blue}{(x-1)^2+y^2=9}$
General Form: $\color{magenta}{x^2+y^2-2x-3=0}$
Refer to the image below for the graph.
Work Step by Step
RECALL:
The standard form of a circle's equation is:
$(x-h)^2 +(y-k)^2=r^2$
where $r$ = radius and $(h, k)$ is the center.
The circle has:
center: $(h, k)=(1, 0)$
$r=3$
Substitute the given values of $h, k,$ and $r$ into the standard form above to obtain:
$(x-1)^2+(y-0)^2=3^2
\\\color{blue}{(x-1)^2+y^2=9}$
Write the equation in general form by squaring each binomial then subtracting $4$ on both sides of the equation to obtain:
$(x-1)^2+y^2=4
\\x^2-2x+1+y^2-4=0
\\\color{magenta}{x^2+y^2-2x-3=0}$
To graph the circle, perform the following steps:
(1) Plot the center $(1, 0)$.
(2) With a radius of $3$ units, plot the following points:
3 units to the left of the center: $(-2, 0)$
3 units to the right of the center: $(4, 0)$
3 units above the center: $(1, 3)$
3 units below the center: $(1, -3)$
(3) Connect the four points above (not including the center) using a smooth curve to form a circle
(Refer to the attached image in the answer part above for the graph.)