Answer
$(x-1)^2+y^2=20$
Work Step by Step
RECALL:
The standard equation of a circle whose center is at the origin is:
$(x-h)^2+(y-k)^2=r^2$
where $r$ = radius
With its center at $(1, 0)$, the tentative equation of the given circle is:
$(x-1)^2+(y-0)^2=r^2
\\(x-1)^2+y^2=r^2$
To find the value of $r^2$, substitute the x and y values of the given point into the tentative equation above to obtain:
$(x-1)^2+y^2=r^2
\\(-3-1)^2+2^2=r^2
\\(-4)^2+4=r^2
\\16+4=r^2
\\20=r^2$
Therefore, the standard form of the equation of the the given circle is:
$(x-1)^2+y^2=20$
