Answer
(a) The circle has a center (0,1) and a radius of 1 unit.
(b) See below.
(c) The only x-intercept is (0,0). There are two y-intercepts: (0,0) and (0,2).
Work Step by Step
First, we need to make sure that the equation is in standard form $(x-h)^2+(y-k)^2=r^2$
In this case, we can see that the equation is already in standard form.
The x-intercepts are all points of a graph when y=0:
$x^2+(0-1)^2=1$
$x^2+1=1$
$x^2=1-1$
$x^2=0$
$\sqrt{x^2}=\sqrt0$
$x=0$
The y-intercepts are all points of a graph when x=0:
$0^2+(y-1)^2=1$
$(y-1)^2=1$
$\sqrt{(y-1)^2}=\sqrt1$
$y_1-1=-1$
$y_1=0$
$y_2-1=1$
$y_2=2$
