College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.4 - Circles - 2.4 Assess Your Understanding - Page 186: 2


$x=\left\{-1, 5\right\}$

Work Step by Step

Take the square root of both sides to obtain: $\sqrt{(x-2)^2}=\pm\sqrt9 \\x-2 = \pm 3$ Add $2$ on both sides to obtain: $x=2\pm3$ Thus, $x_1 =2+3=5 \\x_1=2-3=-1$ Therefore, the solutions are: $x=\left\{-1, 5\right\}$
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