Answer
$x^2+y^2=13$
Work Step by Step
RECALL:
The standard equation of a circle whose center is at the origin is:
$x^2+y^2=r^2$
where $r$ = radius
Thus, the tentative equation of the given circle is:
$x^2+y^2=r^2$
To find the value of $r^2$, substitute the x and y values of the given point into the tentative equation above to obtain:
$x^2+y^2=r^2
\\(-2)^2+3^2=r^2
\\4+9=r^2
\\13=r^2$
Therefore, the standard form of the equation of the given circle is:
$x^2+y^2=13$