College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.4 - Circles - 2.4 Assess Your Understanding: 37

Answer

$x^2+y^2=13$

Work Step by Step

RECALL: The standard equation of a circle whose center is at the origin is: $x^2+y^2=r^2$ where $r$ = radius Thus, the tentative equation of the given circle is: $x^2+y^2=r^2$ To find the value of $r^2$, substitute the x and y values of the given point into the tentative equation above to obtain: $x^2+y^2=r^2 \\(-2)^2+3^2=r^2 \\4+9=r^2 \\13=r^2$ Therefore, the standard form of the equation of the given circle is: $x^2+y^2=13$
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