College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding - Page 695: 30



Work Step by Step

All the combinations of 6 objects 1,2,3,4,5 and 6 taken 3 at a time is $123,124,125,126,134,135,136,145,146,156,234,235,236,245,246,256,345,346,356,456$ so using the combination formula we obtain: $C(6,3)=\frac{6!}{(6-3)!3!}=\frac{6!}{3!3!}=\frac{6\cdot5\cdot4\cdot3!}{3!\cdot3\cdot2\cdot1}=20$ $C(6,3)=20$
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