## College Algebra (10th Edition)

$C(8,6)=28$
Use the combination formula, we obtain: $C(n,r)=\frac{n!}{(n-r)!r!}$ $C(8,6)=\frac{8!}{(8-6)!6!}=\frac{8!}{2!6!}=\frac{8\cdot7\cdot6!}{2\cdot1\cdot6!}=28$