College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding: 28



Work Step by Step

All the combinations of 5 objects a,b,c,d and e taken 2 at a time is $ab, ac,ad,ae,bc,bd,be,cd,ce,de$ Using the combination formula we obtain: $C(5,2)=\frac{5!}{(5-2)!2!}=\frac{5!}{3!2!}=\frac{5\cdot4\cdot3!}{3!\cdot2\cdot1}=10$ $C(5,2)=10$
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