College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding - Page 695: 27



Work Step by Step

All the combinations of 5 objects a,b,c,d and e taken 3 at a time is $abc,abd, abe,acd,ace,ade,bce,bce,bde,cde$ Using the combination formula we obtain: $C(5,3)=\frac{5!}{(5-3)!3!}=\frac{5!}{2!3!}=\frac{5\cdot4\cdot3!}{2\cdot1\cdot3!}=10$ $C(5,3)=10$
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