College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding - Page 695: 10

Answer

$P(8,8)=40,320$

Work Step by Step

Use the permutation formula to obtain: $P(n,r)=\frac{n!}{(n-r)!}$ $0!=1$ $P(8,8)=\frac{8!}{(8-8)!}=\frac{8!}{0!}=\frac{8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1}{1}=40,320$ Or $P(8,8)=8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1=40,320$ $P(8,8)=40,320$
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