College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding: 22

Answer

$C(18,9)=48,620$

Work Step by Step

Using the combination formula, we obtain: $C(n,r)=\frac{n!}{(n-r)!r!}$ $C(18,9)=\frac{18!}{(18-9)!9!}=\frac{18!}{9!9!}=\frac{18\cdot17\cdot16\cdot15\cdot14\cdot13\cdot12\cdot11\cdot10\cdot9!}{9!9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1}=48,620$
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