College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding - Page 695: 14



Work Step by Step

Using the permutation formula, we obtain: $P(8,3)=\frac{8!}{(8-3)!}=\frac{8!}{5!}=\frac{8\cdot7\cdot6\cdot5!}{5!}=336$
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