College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 89


$\displaystyle x=\frac{-1\pm\sqrt{17}}{2}$

Work Step by Step

We are given: $x^{2}+x=4$ $x^{2}+x-4=0$ We solve using the quadratic formula ($a=1,\ b=1,\ c=-4$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\displaystyle x=\frac{-(1)\pm\sqrt{(1)^{2}-4*1*-4}}{2*1}$ $\displaystyle x=\frac{-1\pm\sqrt{1+16}}{2}$ $\displaystyle x=\frac{-1\pm\sqrt{17}}{2}$
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