College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 70


$\displaystyle x=\frac{-\sqrt{2}\pm\sqrt{10}}{2}$ $x=0.87$ or $x=-2.29$

Work Step by Step

We are given: $x^{2}+\sqrt{2}x-2=0$ We solve using the quadratic formula ($a=1,\ b=\sqrt{2},\ c=-2$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\displaystyle x=\frac{-\sqrt{2}\pm\sqrt{(\sqrt{2})^{2}-4*1*-2}}{2*1}$ $\displaystyle x=\frac{-\sqrt{2}\pm\sqrt{2+8}}{2}$ $\displaystyle x=\frac{-\sqrt{2}\pm\sqrt{10}}{2}$ $x=0.87$ or $x=-2.29$
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