College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 61


$\displaystyle x=\frac{-2\pm\sqrt{10}}{2}$

Work Step by Step

$2x(x+2)=3$ $2x^{2}+4x=3$ $2x^{2}+4x-3=0$ We solve using the quadratic formula ($a=2,\ b=4,\ c=-3$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\displaystyle x=\displaystyle \frac{-4\pm\sqrt{4^{2}-4*2*-3}}{2*2}$ $\displaystyle x=\frac{-4\pm\sqrt{16+24}}{4}$ $\displaystyle x=\frac{-4\pm\sqrt{40}}{4}$ $\displaystyle x=\frac{-4\pm\sqrt{4*10}}{4}$ $\displaystyle x=\frac{-4\pm 2\sqrt{10}}{4}$ $\displaystyle x=\frac{-2\pm\sqrt{10}}{2}$
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