College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 100

Answer

(3 ft) $\times$ (6 ft).

Work Step by Step

Let the sheet metal have width x and length 2x. Taking away two 1-foot lengths from the width, and two 1-foot lengths from the height of the sheet, what remains is a base rectangle with area $(x-2)(2x-2) $. The height of the box is 1, so we are given (with volume =4) $(x-2)(2x-2)=4$ $2x^{2}-2x-4x+4=4$ $2x^{2}-6x+4-4=0$ $2x^{2}-6x=0$ $2x(x-3)=0$ The x=0 solution makes no sense, so the only solution is x=$3$. The width is 3 ft, so the length is $2x=6$ ft. The original sheet is (3 ft) $\times$ (6 ft).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.