College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 60


$\displaystyle x=\frac{5\pm\sqrt{37}}{6}$

Work Step by Step

$\displaystyle \frac{3}{5}x^{2}-x=\frac{1}{5}$ We multiply by $5$: $5(\displaystyle \frac{3}{5}x^{2}-x)=5*\frac{1}{5}$ $3x^{2}-5x=1$ $3x^{2}-5x-1=0$ We solve using the quadratic formula ($a=3,\ b=-5,\ c=-1$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\displaystyle x=\frac{-(-5)\pm\sqrt{(-5)^{2}-4*3*-1}}{2*3}$ $\displaystyle x=\frac{5\pm\sqrt{25+12}}{6}$ $\displaystyle x=\frac{5\pm\sqrt{37}}{6}$
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