College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 78


two unequal real solutions

Work Step by Step

RECALL The nature of solutions using the quadratic equation $ax^2+bx+c=0$ can be determined using the value of its discriminant $b^2-4ac$. If the value of the discriminant is: (1) negative, then the equation has no real solutions; (2) zero, then the equation has one repeated real solution; and (3) positive, then there are two unequal real solutions. The given quadratic equation has : $a=2 \\b=-3 \\c=-7$ Solve for the discriminant to obtain: $=b^2-4ac \\=(-3)^2-4(2)(-7) \\=9-(-56) \\=9+56 \\=65$ The discriminant is positive; therefore the equation has two unequal real solutions.
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