College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 79

Answer

The solution set is $\left\{-\sqrt5, \sqrt5\right\}$.

Work Step by Step

Add $5$ to both sides to obtain: $x^2 = 5$ Take the square root of both sides to obtain: $x = \pm \sqrt{5}$ Thus, the solution set is $\left\{-\sqrt5, \sqrt5\right\}$.
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