Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 7

Answer

$cos~x=-\frac{2}{5}$ $sin~x=\frac{\sqrt {21}}{5}$ $tan~x=-\frac{\sqrt {21}}{2}$ $cot~x=-\frac{2\sqrt {21}}{21}$ $csc~x=\frac{5\sqrt {21}}{21}$

Work Step by Step

$sec~x=\frac{1}{cos~x}\lt0$ $tan~x=\frac{sin~x}{cos~x}\lt0$ We can conclude that: $cos~x\lt0$ $sin~x\gt0$ $cot~x=\frac{1}{tan~x}\lt0$ $csc~x=\frac{1}{sin~x}\gt0$ $cos~x=\frac{1}{sec~x}=\frac{1}{-\frac{5}{2}}=-\frac{2}{5}$ $cos^2x+sin^2x=1$ $sin^2x=1-\frac{4}{25}=\frac{21}{25}$ $sin~x=\frac{\sqrt {21}}{5}$ $tan~x=\frac{sin~x}{cos~x}=\frac{\frac{\sqrt {21}}{5}}{-\frac{2}{5}}=-\frac{\sqrt {21}}{2}$ $cot~x=\frac{cos~x}{sin~x}=\frac{-\frac{2}{5}}{\frac{\sqrt {21}}{5}}=-\frac{2}{\sqrt {21}}=-\frac{2\sqrt {21}}{21}$ $csc~x=\frac{1}{sin~x}=\frac{5}{\sqrt {21}}=\frac{5\sqrt {21}}{21}$
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