Answer
$tan~θ~csc~θ=sec~θ$
Work Step by Step
We know that:
$tan~θ=\frac{sin~θ}{cos~θ}$
$csc~θ=\frac{1}{sin~θ}$
So:
$tan~θ~csc~θ=\frac{sin~θ}{cos~θ}·\frac{1}{sin~θ}=\frac{1}{cos~θ}=sec~θ$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 33
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
