Answer
$6~cos^2x+5~cos~x-6=(3~cos~x-2)(2~cos~x+3)$
Work Step by Step
$6~cos^2x+5~cos~x-6=6~cos^2x+9~cos~x-4~cos~x-6=$
$3~cos~x~(2~cos~x+3)-2~(2~cos~x+3)=(3~cos~x-2)(2~cos~x+3)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 30
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