Answer
$tan^2x-tan^2x~sin^2x=sin^2x$
Work Step by Step
Pythagorean Identity:
$cos^2x+sin^2x=1$
$cos^2x=1-sin^2x$
$tan^2x-tan^2x~sin^2x=tan^2x(1-sin^2x)=\frac{sin^2x}{cos^2x}cos^2x=sin^2x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 21
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