Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 21



Work Step by Step

Pythagorean Identity: $cos^2x+sin^2x=1$ $cos^2x=1-sin^2x$ $tan^2x-tan^2x~sin^2x=tan^2x(1-sin^2x)=\frac{sin^2x}{cos^2x}cos^2x=sin^2x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.