Answer
$\frac{sin^2y}{1-cos~y}=1+cos~y$
Work Step by Step
$\frac{sin^2y}{1-cos~y}=\frac{1-cos^2y}{1-cos~y}=\frac{(1+cos~y)(1-cos~y)}{1-cos~y}=1+cos~y$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 49
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