Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 34



Work Step by Step

We know that: $tan~x=\frac{sin~x}{cos~x}$ $tan(-x)=-tan~x=-\frac{sin~x}{cos~x}$ So: $tan(-x)~cos~x=-\frac{sin~x}{cos~x}cos~x=-sin~x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.