Answer
$arccos(\frac{\sqrt 2}{2})=\frac{\pi}{4}$
Work Step by Step
The range of $arccos~x$ is $[0,\pi]$. So,
$arccos(\frac{\sqrt 2}{2})=\frac{\pi}{4}$, because $cos(\frac{\pi}{4})=\frac{\sqrt 2}{2}$ and $0\leq\frac{\pi}{4}\leq\pi$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - Review Questions - Page 501: 94
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