Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Review Questions - Page 501: 92



Work Step by Step

The range of $arcsin~x$ is $[-\frac{\pi}{2},\frac{\pi}{2}]$. So, $arcsin(-1)=-\frac{\pi}{2}$ because $sin(-\frac{\pi}{2})=-1$ and $-\frac{\pi}{2}\leq-\frac{\pi}{2}\leq\frac{\pi}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.