Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Review Questions - Page 501: 57


$sin(-150°)=-\frac{1}{2}$ $cos(-150°)=-\frac{\sqrt 3}{2}$ $tan(-150°)=\frac{\sqrt 3}{3}$

Work Step by Step

Let $θ'$ be the reference angle. We must have that $0°\leqθ'\lt360°$ $θ'=θ+n·360°$, where $n$ is an integer. $θ'=-150°+360°=210°$ $sin(-150°)=sin~210°=-\frac{1}{2}$ $cos(-150°)=cos~210°=-\frac{\sqrt 3}{2}$ $tan(-150°)=tan~210°=\frac{\sqrt 3}{3}$
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