Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Review Questions - Page 501: 61


$sin(-\frac{7\pi}{3})=-\frac{\sqrt 3}{2}$ $cos(-\frac{7\pi}{3})=\frac{1}{2}$ $tan(-\frac{7\pi}{3})=-\sqrt 3$

Work Step by Step

Let $θ'$ be the reference angle. We must have that $0\leqθ'\lt2\pi$ $θ'=θ+n·2\pi$, where $n$ is an integer. $θ'=-\frac{7\pi}{3}+2·2\pi=\frac{5\pi}{3}$ $sin(-\frac{7\pi}{3})=sin\frac{5\pi}{3}=-\frac{\sqrt 3}{2}$ $cos(-\frac{7\pi}{3})=cos\frac{5\pi}{3}=\frac{1}{2}$ $tan(-\frac{7\pi}{3})=tan\frac{5\pi}{3}=-\sqrt 3$
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