Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Review Questions - Page 501: 56


$sin~120°=\frac{\sqrt 3}{2}$ $cos~120°=-\frac{1}{2}$ $tan~120°=-\sqrt 3$

Work Step by Step

Let $θ'$ be the reference angle. We must have that $0°\leqθ'\lt360°$ But, since $0°\leqθ=120°\lt360°$, it is not necessary to find the reference angle. $sin~120°=\frac{\sqrt 3}{2}$ $cos~120°=-\frac{1}{2}$ $tan~120°=-\sqrt 3$
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