Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Review Questions - Page 501: 59


$sin(\frac{\pi}{3})=\frac{\sqrt 3}{2}$ $cos(\frac{\pi}{3})=\frac{1}{2}$ $tan(\frac{\pi}{3})=\sqrt 3$

Work Step by Step

Let $θ'$ be the reference angle. We must have that $0\leqθ'\lt2\pi$ But, since $0\leqθ=\frac{\pi}{3}\lt2\pi$, it is not necessary to find a reference angle. $sin(\frac{\pi}{3})=\frac{\sqrt 3}{2}$ $cos(\frac{\pi}{3})=\frac{1}{2}$ $tan(\frac{\pi}{3})=\sqrt 3$
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