Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 396: 84



Work Step by Step

$N=3500(10^{-0.012x})$ $22=3500(10^{-0.012x})$ $\frac{22}{3500}=10^{-0.012x}$ $\log\frac{22}{3500}=\log10^{-0.012x}$ $-0.012x=\log\frac{22}{3500}$ $x=\frac{\log\frac{22}{3500}}{-0.012}=183.47$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.