Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 396: 78

Answer

$x=2.718$
1564205159

Work Step by Step

$\frac{1-\ln x}{x^2}=0$ $1-\ln x=0$ $1=\ln x$ $e^{1}=e^{\ln x}$ $x=2.718$ Notice that $2.718 $ lies in the domain of $\ln x$ and in the domain of $\frac{1-\ln x}{x^2}$
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