## Algebra and Trigonometry 10th Edition

$x=2.718$
$\frac{1-\ln x}{x^2}=0$ $1-\ln x=0$ $1=\ln x$ $e^{1}=e^{\ln x}$ $x=2.718$ Notice that $2.718$ lies in the domain of $\ln x$ and in the domain of $\frac{1-\ln x}{x^2}$