Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 396: 74

Answer

$x=0$ $x=2$
1564203731

Work Step by Step

$-x^2e^{-x}+2xe^{-x}=0$ $-xe^{-x}(x-2)=0$ Since $e^{-x}\gt0$ for any $x$ in the domain of $e^{-x}$ $-xe^{-x}=0$ $x=0$ $x-2=0$ $x=2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.