## Algebra and Trigonometry 10th Edition

$x=0$ $x=2$
$-x^2e^{-x}+2xe^{-x}=0$ $-xe^{-x}(x-2)=0$ Since $e^{-x}\gt0$ for any $x$ in the domain of $e^{-x}$ $-xe^{-x}=0$ $x=0$ $x-2=0$ $x=2$