Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 396: 77

Answer

$x=0.368$
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Work Step by Step

$\frac{1+\ln x}{2}=0$ $1+\ln x=0$ $\ln x=-1$ $e^{\ln x}=e^{-1}$ $x=0.368$ Notice that $0.368$ lies in the domain of $\ln x$
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