Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 396: 76

Answer

$x=\frac{1}{2}$

Work Step by Step

$e^{-2x}-2xe^{-2x}=0$ $-e^{-x}(-1+2x)=0$ Since $e^{-x}\gt0$ for any $x$ in the domain of $e^{-x}$: $-1+2x=0$ $2x=1$ $x=\frac{1}{2}$
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