## Algebra and Trigonometry 10th Edition

$x=\frac{1}{2}$
$e^{-2x}-2xe^{-2x}=0$ $-e^{-x}(-1+2x)=0$ Since $e^{-x}\gt0$ for any $x$ in the domain of $e^{-x}$: $-1+2x=0$ $2x=1$ $x=\frac{1}{2}$