Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 396: 75

Answer

$x=1$
1564204028

Work Step by Step

$-xe^{-x}+e^{-x}=0$ $-e^{-x}(x-1)=0$ Since $e^{-x}\gt0$ for any $x$ in the domain of $e^{-x}$: $x-1=0$ $x=1$
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