## Algebra and Trigonometry 10th Edition

$\log(3x+4)=\log(x-10)$ Using the One-to-One Property: $3x+4=x-10$ $2x=-14$ $x=-7$ Check the solution: $\log(3x+4)=\log(3(-7)+4)=\log(-17)$. But the domain of $\log x$ is $(0,∞)$. So, $x=-7$ is not a valid solution.