Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 395: 55



Work Step by Step

$\ln x-\ln(x+1)=2$ $\ln\frac{x}{x+1}=2$ $e^{\ln\frac{x}{x+1}}=e^2$ $\frac{x}{x+1}=e^2$ $x=e^2x+e^2$ $x(1-e^2)=e^2$ $x=\frac{e^2}{1-e^2}=-1.156$
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