Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 395: 57


$x=-3$ $x=-2$

Work Step by Step

$\ln(x+5)=\ln(x-1)-\ln(x+1)$ $\ln(x+5)=\ln\frac{x-1}{x+1}$ Using the One-to-One Property: $x+5=\frac{x-1}{x+1}$ $(x+5)(x+1)=x-1$ $x^2+6x+5=x-1$ $x^2+5x+6=0~~$ (Make: $5x=2x+3x$) $x^2+2x+3x+6=0$ $x(x+2)+3(x+2)=0$ $(x+3)(x+2)=0$ $x+3=0$ $x=-3$ $x+2=0$ $x=-2$
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