## Algebra and Trigonometry 10th Edition

$x=-3$ $x=-2$
$\ln(x+5)=\ln(x-1)-\ln(x+1)$ $\ln(x+5)=\ln\frac{x-1}{x+1}$ Using the One-to-One Property: $x+5=\frac{x-1}{x+1}$ $(x+5)(x+1)=x-1$ $x^2+6x+5=x-1$ $x^2+5x+6=0~~$ (Make: $5x=2x+3x$) $x^2+2x+3x+6=0$ $x(x+2)+3(x+2)=0$ $(x+3)(x+2)=0$ $x+3=0$ $x=-3$ $x+2=0$ $x=-2$