Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 395: 37

Answer

$x=-1.710$

Work Step by Step

$3^x=2^{x-1}$ $3^x=2^x·2^{-1}$ $\frac{3^x}{2^x}=\frac{1}{2}$ $(\frac{3}{2})^x=\frac{1}{2}$ $\log_{\frac{3}{2}}(\frac{3}{2})^x=\log_{\frac{3}{2}}\frac{1}{2}$ $x=\log_{\frac{3}{2}}\frac{1}{2}=\frac{\ln\frac{1}{2}}{\ln\frac{3}{2}}=-1.710$
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