Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 395: 25



Work Step by Step

$3^{2x}=80$ $\log_33^{2x}=\log_380~~$ (Using the Inverse Property: $\log_aa^x=x$): $2x=\log_380$ $x=\frac{1}{2}\log_380=\frac{1}{2}\frac{\ln80}{\ln3}\approx1.994$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.