Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 395: 21

Answer

$x=1.465$

Work Step by Step

$4(3^x)=20$ $3^x=\frac{20}{4}=5$ $\log_33^x=\log_35~$ (Using the Inverse Property: $\log_aa^x=x$): $x=\log_35=\frac{\log5}{\log3}\approx1.465$
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