Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - Review Exercises - Page 841: 62



Work Step by Step

$\displaystyle \sum_{k=1}^{∞}1.3(\frac{1}{10})^{k-1}=1.3(\frac{1}{10})^0+1.3(\frac{1}{10})^1+1.3(\frac{1}{10})^2+...$ $a_1=1.3(\frac{1}{10})^0=1.3$ $r=\frac{a_2}{a_1}=\frac{1.3(\frac{1}{10})^1}{1.3(\frac{1}{10})^0}=\frac{1}{10}$ $S=\frac{a_1}{1-r}=\frac{1.3}{1-\frac{1}{10}}=\frac{1.3}{\frac{9}{10}}=\frac{13}{9}=1.444...$
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