Answer
$(a-3b)^5=a^5-15a^4b+90a^3b^2-270a^2b^3+405ab^4-243b^5$
Work Step by Step
$(a-3b)^5=~_5C_0(a)^5+~_5C_1(a)^4(-3b)^1+~_5C_2(a)^3(-3b)^2+~_5C_3(a)^2(-3b)^3+~_5C_4(a)^1(-3b)^4+~_5C_5(-3b)^5=a^5-15a^4b+90a^3b^2-270a^2b^3+405ab^4-243b^5$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - Review Exercises - Page 841: 84
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