Answer
$S=8$
Work Step by Step
$\displaystyle \sum_{i=0}^{∞}(\frac{7}{8})^i=(\frac{7}{8})^0+(\frac{7}{8})^1+(\frac{7}{8})^2+...$
$a_1=(\frac{7}{8})^0=1$
$r=\frac{a_2}{a_1}=\frac{(\frac{7}{8})^1}{(\frac{7}{8})^0}=\frac{7}{8}$
$S=\frac{a_1}{1-r}=\frac{1}{1-\frac{7}{8}}=\frac{1}{\frac{1}{8}}=8$
