# Chapter 11 - Review Exercises - Page 841: 48

$a_n=25(0.2)^n$ $a_1=5$ $a_2=1$ $a_3=0.2$ $a_4=0.04$ $a_5=0.008$

#### Work Step by Step

$a_1=5,~~r=0.2$ The nth term of a geometric sequence: $a_n=a_1r^{n-1}$ $a_n=5(0.2)^{n-1}=5(0.2)^n(0.2)^{-1}=\frac{5}{0.2}(0.2)^n=25(0.2)^n$ $a_2=25(0.2)^2=25(0.04)=1$ $a_3=25(0.2)^3=25(0.008)=0.2$ $a_4=25(0.2)^4=25(0.0016)=0.04$ $a_5=25(0.2)^5=25(0.00032)=0.008$

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