Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - Review Exercises - Page 841: 57



Work Step by Step

$\displaystyle \sum_{i=1}^{5}10(0.6)^{i-1}=10(0.6)^0+10(0.6)^1+10(0.6)^2+...+10(0.6)^5$ $a_1=10(0.6)^0=10$ $r=\frac{a_2}{a_1}=\frac{10(0.6)^1}{10(0.6)^0}=0.6$ $S_5=a_1(\frac{1-r^n}{1-r})=10(\frac{1-0.6^5}{1-0.6})=10~\frac{0.92224}{0.4}=23.056$
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